b^2-3bc-28c^2=0

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Solution for b^2-3bc-28c^2=0 equation:


Simplifying
b2 + -3bc + -28c2 = 0

Reorder the terms:
-3bc + b2 + -28c2 = 0

Solving
-3bc + b2 + -28c2 = 0

Solving for variable 'b'.

Factor a trinomial.
(b + -7c)(b + 4c) = 0

Subproblem 1

Set the factor '(b + -7c)' equal to zero and attempt to solve: Simplifying b + -7c = 0 Solving b + -7c = 0 Move all terms containing b to the left, all other terms to the right. Add '7c' to each side of the equation. b + -7c + 7c = 0 + 7c Combine like terms: -7c + 7c = 0 b + 0 = 0 + 7c b = 0 + 7c Remove the zero: b = 7c Simplifying b = 7c

Subproblem 2

Set the factor '(b + 4c)' equal to zero and attempt to solve: Simplifying b + 4c = 0 Solving b + 4c = 0 Move all terms containing b to the left, all other terms to the right. Add '-4c' to each side of the equation. b + 4c + -4c = 0 + -4c Combine like terms: 4c + -4c = 0 b + 0 = 0 + -4c b = 0 + -4c Remove the zero: b = -4c Simplifying b = -4c

Solution

b = {7c, -4c}

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